MathCompass

Power of a Point

Geometry Advanced

πŸ“‹ Prerequisites

Power of a Point is one of the most useful theorems in competition geometry. It relates the lengths of segments created when two lines intersect a circle β€” whether the intersection is inside the circle (two chords) or outside (two secants, or a secant and a tangent). One formula, three cases.

πŸ“š Key Concepts

What Is the "Power" of a Point?

For a point P and a circle with center O and radius r:

\[ \text{Power of P} = OP^2 - r^2 \]

The key insight: for any line through P intersecting the circle at X and Y, the product $ PX \cdot PY $ is constant β€” it equals the power of P (up to sign).

Case 1: Intersecting Chords (Point Inside)

If two chords AB and CD intersect at point P inside the circle:

\[ PA \cdot PB = PC \cdot PD \]

The products of the segments of each chord are equal.

Why: Triangles PAC and PDB are similar by AA (vertical angles + inscribed angles subtending the same arc).

Case 2: Secant-Secant (Point Outside)

If from point P outside the circle, two secants are drawn β€” one intersecting the circle at A and B, the other at C and D (with PA < PB, PC < PD):

\[ PA \cdot PB = PC \cdot PD \]

\(Whole secant \\times external segment is constant for both secants.\)

Important: PA is the entire length from P to the far intersection B, times the near segment PA. Wait β€” \(more precisely: external part \\times whole = external part \\times whole.\)

Standard notation: if the secant hits the circle first at A, then continues to B (farther from P):

$ PA_{outside} \times PB_{whole} = PC_{outside} \times PD_{whole} $

Case 3: Tangent-Secant (Point Outside)

If from point P outside the circle, a tangent touches at T and a secant passes through A (near) and B (far):

\[ PT^2 = PA \cdot PB \]

The square of the tangent length equals the product of the entire secant and its external segment.

This is the limit case of the secant-secant theorem where the two intersection points coincide.

Mnemonic: Same Formula, Three Looks

All three cases say the same thing: for a point P and a line through P cutting the circle at X and Y, the product $PX \cdot PY$ is constant (depends only on P and the circle, not the line).

Radical Axis (Introduction)

The set of points with equal power with respect to two circles is a line called the radical axis.

⚠️ Common Mistake: In the secant-secant case, make sure you multiply the entire secant length (from the external point all the way to the far intersection) by the external segment (from the point to the near intersection). Don't just multiply the two parts of the chord that are inside the circle β€” that's the \(intersecting chords formula (for points inside). Outside: whole \\times external. Inside: part \\times part.\)
πŸ’‘ Key Insight: When you see two chords crossing, or two secants from a point, or a tangent with a secant, Power of a Point should immediately come to mind. It's often the fastest way to find a missing length. The trick is identifying which case you have (inside vs. outside) and setting up the product correctly. Label the points carefully: for an external point, identify the near intersection and far intersection on each secant.

✏️ Example Problems

πŸ“ Example 1 (Intersecting chords)

Two chords AB and CD intersect at point P inside a circle.
PA = 4, PB = 9, PC = 6. What is the length of PD?

Power of a Point β€” Intersecting Chords:

\[ PA \cdot PB = PC \cdot PD \]

Step 1: Plug in the known values.

$ 4 \times 9 = 6 \times PD $

Step 2: Solve for PD.

$ 36 = 6 \cdot PD $

$ PD = 6 $

Check: \(4 \\times 9 = 36, 6 \\times 6 = 36. Equal products.\) βœ“

Answer: 6

πŸ“ Example 2 (Tangent-secant)

From a point P outside a circle, tangent PT has length 12.
A secant from P passes through the circle, with PA = 8 (external segment).
What is the length PB of the entire secant?

Power of a Point β€” Tangent-Secant:

\[ PT^2 = PA \cdot PB \]

Step 1: PT = 12, PA = 8 (external segment from P to near intersection A).

PB = whole secant (from P through A to far intersection B).

Step 2: Plug in values.

$ 12^2 = 8 \times PB $

$ 144 = 8 \cdot PB $

$ PB = 18 $

Check: \(PA \\times PB = 8 \\times 18 = 144 = 12^{2} = PT^{2}.\) βœ“

Note: The chord AB inside the circle would be PB - PA = 18 - 8 = 10.

Answer: 18

πŸ“ Example 3 (Secant-secant)

From point P outside a circle, two secants are drawn.
First secant: PA = 5 (external), PB = 12 (whole).
Second secant: PC = 4 (external). Find the whole length PD.

Power of a Point β€” Secant-Secant:

\[ PA \cdot PB = PC \cdot PD \]

\((external \\times whole = external \\times whole)\)

Step 1: Plug in known values.

PA = 5, PB = 12, PC = 4. Find PD.

$ 5 \times 12 = 4 \times PD $

Step 2: Solve.

$ 60 = 4 \cdot PD $

$ PD = 15 $

Check: \(5 \\times 12 = 60, 4 \\times 15 = 60. Equal.\) βœ“

Answer: 15

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