3D geometry extends 2D ideas into space β volume, surface area, and spatial relationships. The good news: most competition 3D problems reduce to 2D problems if you take the right cross-section. Find the right slice, draw it flat, and use everything you already know about triangles and circles.
For a rectangular prism with dimensions $ l, w, h $, the distance between opposite corners (space diagonal):
\[ d = \sqrt{l}}^2 + w^2 + h^2} \]
This is the 3D Pythagorean theorem β apply it twice: first find a face diagonal, then use that as one leg with the height.
Cube special case: $ d = s\sqrt{3} $
Many 3D problems become 2D problems if you take the right cross-sectional slice:
Strategy: identify the plane that contains the information you need, draw the cross-section, and solve in 2D.
If two solids are similar with scale factor $k$ (ratio of corresponding linear dimensions):
\(Linear scale factor k \to area scales by k^{2}, volume by k^{3}. This is the 3D version of the similarity area ratio from 2D.\)
If two solids have the same height and the same cross-sectional area at every level, they have the same volume.
Intuition: same height, same "width" \(at every height \to same total volume, regardless of shape.\)
Used to derive volume formulas and solve tricky volume problems where direct calculation is hard.
Why 1/3? A cone/pyramid of the same base and height as a cylinder/prism has exactly 1/3 the volume.
Three pyramids of equal volume make up the corresponding prism. You can think of it as the 3D analog of the triangle area factor of 1/2.
Volume of cylinder: $ V = \pi r^2 h $
Step 1: Identify values: r = 3, h = 7
Step 2: Compute base area first.
Base area = $ \pi r^2 = \pi (3)^2 = 9\pi $
Step 3: Multiply by height.
\[ V = 9\pi \times 7 = 63\pi \]
The coefficient is 63.
Answer: 63
Step 1: Find the diagonal of one face (2D Pythagoras).
Face diagonal = $ \sqrt{5^2 + 5^2} = \sqrt{25 + 25} = \sqrt{50} = 5\sqrt{2} $
Step 2: Use the face diagonal and an edge to find the space diagonal (another Pythagoras).
\[ \text{Space diagonal} = \sqrt{(5\sqrt{2})^2 + 5^2} \]
$ = \sqrt{50 + 25} = \sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3} $
Direct formula: For cube with side s: space diagonal = $ s\sqrt{3} $
$ 5\sqrt{3} $, so a = 5, b = 3
a + b = 5 + 3 = 8
Answer: 8
Similar solids: \(linear scale factor k \to volume scales by\) $k^3$
Step 1: Linear ratio (small : large) = 2 : 3
Scale factor from small to large: $ k = \frac{3}{2} $
Step 2: Volume ratio = $k^3$.
\[ \text{Volume ratio} = \left(\frac{3}{2}\right)^3 = \frac{27}{8} \]
Step 3: \(Larger volume = smaller volume \times volume ratio.\)
$ V_{large} = 32 \times \frac{27}{8} = 4 \times 27 = 108 $
Check with sphere formula:
Small: $ \frac{4}{3}\pi(2)^3 = \frac{32}{3}\pi = 32 $ (in our units)
Large: $ \frac{4}{3}\pi(3)^3 = \frac{108}{3}\pi = 108\pi/\text{units} = 108 $. β
Answer: 108